1/2(2x+4)^2=4

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Solution for 1/2(2x+4)^2=4 equation: 



1/2(2x+4)^2=4

We move all terms to the left:

1/2(2x+4)^2-(4)=0



Domain of the equation: 2(2x+4)^2!=0

x∈R



We multiply all the terms by the denominator


-4*2(2x+4)^2+1=0

Wy multiply elements

-8x(2+1=0

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